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Add Swiss-French variants of numbers between 60 and 100.
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113
num2words/lang_FR_CH.py
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113
num2words/lang_FR_CH.py
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# -*- encoding: utf-8 -*-
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# Copyright (c) 2003, Taro Ogawa. All Rights Reserved.
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# Copyright (c) 2013, Savoir-faire Linux inc. All Rights Reserved.
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# This library is free software; you can redistribute it and/or
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# modify it under the terms of the GNU Lesser General Public
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# License as published by the Free Software Foundation; either
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# version 2.1 of the License, or (at your option) any later version.
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# This library is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
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# Lesser General Public License for more details.
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# You should have received a copy of the GNU Lesser General Public
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# License along with this library; if not, write to the Free Software
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# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston,
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# MA 02110-1301 USA
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from __future__ import unicode_literals
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from .lang_EU import Num2Word_EU
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class Num2Word_FR_CH(Num2Word_EU):
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def setup(self):
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self.negword = "moins "
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self.pointword = "virgule"
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self.errmsg_nonnum = u"Seulement des nombres peuvent être convertis en mots."
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self.errmsg_toobig = u"Nombre trop grand pour être converti en mots."
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self.exclude_title = ["et", "virgule", "moins"]
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self.mid_numwords = [(1000, "mille"), (100, "cent"), (90, "nonante"),
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(80, "huitante"), (70, "septante"), (60, "soixante"),
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(50, "cinquante"), (40, "quarante"),
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(30, "trente")]
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self.low_numwords = ["vingt", "dix-neuf", "dix-huit", "dix-sept",
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"seize", "quinze", "quatorze", "treize", "douze",
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"onze", "dix", "neuf", "huit", "sept", "six",
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"cinq", "quatre", "trois", "deux", "un", "zéro"]
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self.ords = {
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"cinq": "cinquième",
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"neuf": "neuvième",
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}
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def merge(self, curr, next):
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ctext, cnum, ntext, nnum = curr + next
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if cnum == 1:
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if nnum < 1000000:
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return next
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else:
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# if (not (cnum - 80)%100 or not cnum%100) and ctext[-1] == "s":
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# ctext = ctext[:-1]
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if (cnum<1000 and nnum != 1000 and ntext[-1] != "s"
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and not nnum%100):
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ntext += "s"
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if nnum < cnum < 100:
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if nnum % 10 == 1:# and cnum != 80:
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return ("%s et %s"%(ctext, ntext), cnum + nnum)
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return ("%s-%s"%(ctext, ntext), cnum + nnum)
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elif nnum > cnum:
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return ("%s %s"%(ctext, ntext), cnum * nnum)
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return ("%s %s"%(ctext, ntext), cnum + nnum)
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# Is this right for such things as 1001 - "mille unième" instead of
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# "mille premier"?? "millième"??
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def to_ordinal(self,value):
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self.verify_ordinal(value)
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if value == 1:
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return "premier"
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word = self.to_cardinal(value)
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for src, repl in self.ords.items():
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if word.endswith(src):
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word = word[:-len(src)] + repl
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break
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else:
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if word[-1] == "e":
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word = word[:-1]
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word = word + "ième"
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return word
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def to_ordinal_num(self, value):
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self.verify_ordinal(value)
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out = str(value)
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out += {"1" : "er" }.get(out[-1], "me")
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return out
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def to_currency(self, val, longval=True, old=False):
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hightxt = "Euro/s"
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if old:
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hightxt="franc/s"
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return self.to_splitnum(val, hightxt=hightxt, lowtxt="centime/s",
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jointxt="et",longval=longval)
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n2w = Num2Word_FR_CH()
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to_card = n2w.to_cardinal
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to_ord = n2w.to_ordinal
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to_ordnum = n2w.to_ordinal_num
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def main():
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for val in [ 1, 11, 12, 21, 31, 33, 71, 80, 81, 91, 99, 100, 101, 102, 155,
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180, 300, 308, 832, 1000, 1001, 1061, 1100, 1500, 1701, 3000,
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8280, 8291, 150000, 500000, 1000000, 2000000, 2000001,
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-21212121211221211111, -2.121212, -1.0000100]:
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n2w.test(val)
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n2w.test(1325325436067876801768700107601001012212132143210473207540327057320957032975032975093275093275093270957329057320975093272950730)
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print n2w.to_currency(112121)
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print n2w.to_year(1996)
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if __name__ == "__main__":
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main()
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