mirror of
https://github.com/bblaz/num2words.git
synced 2025-12-06 06:42:25 +00:00
53b4518afb
Some maintainers for different linux distribution are having some problems with the encoding on different python versions. This change intents to make all python files define explicitly the encoding, license and unix line separators. Remove one example of the README.rst file where a possible non UTF-8 character is used.
247 lines
8.5 KiB
Python
247 lines
8.5 KiB
Python
# -*- coding: utf-8 -*-
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# Copyright (c) 2003, Taro Ogawa. All Rights Reserved.
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# Copyright (c) 2013, Savoir-faire Linux inc. All Rights Reserved.
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# This library is free software; you can redistribute it and/or
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# modify it under the terms of the GNU Lesser General Public
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# License as published by the Free Software Foundation; either
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# version 2.1 of the License, or (at your option) any later version.
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# This library is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
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# Lesser General Public License for more details.
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# You should have received a copy of the GNU Lesser General Public
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# License along with this library; if not, write to the Free Software
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# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston,
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# MA 02110-1301 USA
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from __future__ import division, unicode_literals
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import re
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from .lang_EU import Num2Word_EU
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DOLLAR = ('dólar', 'dólares')
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CENTS = ('cêntimo', 'cêntimos')
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class Num2Word_PT(Num2Word_EU):
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CURRENCY_FORMS = {
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'AUD': (DOLLAR, CENTS),
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'CAD': (DOLLAR, CENTS),
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'EUR': (('euro', 'euros'), CENTS),
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'GBP': (('libra', 'libras'), ('péni', 'pence')),
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'USD': (DOLLAR, CENTS),
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}
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GIGA_SUFFIX = None
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MEGA_SUFFIX = "ilião"
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def setup(self):
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super(Num2Word_PT, self).setup()
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lows = ["quatr", "tr", "b", "m"]
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self.high_numwords = self.gen_high_numwords([], [], lows)
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self.negword = "menos "
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self.pointword = "vírgula"
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self.exclude_title = ["e", "vírgula", "menos"]
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self.mid_numwords = [
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(1000, "mil"), (100, "cem"), (90, "noventa"),
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(80, "oitenta"), (70, "setenta"), (60, "sessenta"),
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(50, "cinquenta"), (40, "quarenta"), (30, "trinta")
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]
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self.low_numwords = [
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"vinte", "dezanove", "dezoito", "dezassete", "dezasseis",
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"quinze", "catorze", "treze", "doze", "onze", "dez",
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"nove", "oito", "sete", "seis", "cinco", "quatro", "três", "dois",
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"um", "zero"
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]
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self.ords = [
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{
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0: "",
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1: "primeiro",
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2: "segundo",
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3: "terceiro",
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4: "quarto",
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5: "quinto",
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6: "sexto",
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7: "sétimo",
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8: "oitavo",
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9: "nono",
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},
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{
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0: "",
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1: "décimo",
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2: "vigésimo",
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3: "trigésimo",
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4: "quadragésimo",
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5: "quinquagésimo",
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6: "sexagésimo",
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7: "septuagésimo",
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8: "octogésimo",
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9: "nonagésimo",
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},
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{
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0: "",
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1: "centésimo",
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2: "ducentésimo",
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3: "tricentésimo",
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4: "quadrigentésimo",
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5: "quingentésimo",
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6: "seiscentésimo",
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7: "septigentésimo",
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8: "octigentésimo",
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9: "nongentésimo",
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},
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]
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self.thousand_separators = {
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3: "milésimo",
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6: "milionésimo",
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9: "milésimo milionésimo",
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12: "bilionésimo",
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15: "milésimo bilionésimo"
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}
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self.hundreds = {
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1: "cento",
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2: "duzentos",
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3: "trezentos",
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4: "quatrocentos",
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5: "quinhentos",
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6: "seiscentos",
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7: "setecentos",
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8: "oitocentos",
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9: "novecentos",
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}
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def merge(self, curr, next):
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ctext, cnum, ntext, nnum = curr + next
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if cnum == 1:
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if nnum < 1000000:
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return next
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ctext = "um"
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elif cnum == 100 and not nnum % 1000 == 0:
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ctext = "cento"
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if nnum < cnum:
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if cnum < 100:
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return ("%s e %s" % (ctext, ntext), cnum + nnum)
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return ("%s e %s" % (ctext, ntext), cnum + nnum)
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elif (not nnum % 1000000000) and cnum > 1:
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ntext = ntext[:-4] + "liões"
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elif (not nnum % 1000000) and cnum > 1:
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ntext = ntext[:-4] + "lhões"
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# correct "milião" to "milhão"
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if ntext == 'milião':
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ntext = 'milhão'
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if nnum == 100:
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ctext = self.hundreds[cnum]
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ntext = ""
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else:
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ntext = " " + ntext
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return (ctext + ntext, cnum * nnum)
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def to_cardinal(self, value):
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result = super(Num2Word_PT, self).to_cardinal(value)
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# Transforms "mil e cento e catorze" into "mil cento e catorze"
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# Transforms "cem milhões e duzentos mil e duzentos e dez" em "cem
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# milhões duzentos mil duzentos e dez" but "cem milhões e duzentos
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# mil e duzentos" in "cem milhões duzentos mil e duzentos" and not in
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# "cem milhões duzentos mil duzentos"
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for ext in (
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'mil', 'milhão', 'milhões', 'mil milhões',
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'bilião', 'biliões', 'mil biliões'):
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if re.match('.*{} e \\w*entos? (?=.*e)'.format(ext), result):
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result = result.replace(
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'{} e'.format(ext), '{}'.format(ext)
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)
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return result
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# for the ordinal conversion the code is similar to pt_BR code,
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# although there are other rules that are probably more correct in
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# Portugal. Concerning numbers from 2000th on, saying "dois
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# milésimos" instead of "segundo milésimo" (the first number
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# would be used in the cardinal form instead of the ordinal) is better.
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# This was not implemented.
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# source:
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# https://ciberduvidas.iscte-iul.pt/consultorio/perguntas/a-forma-por-extenso-de-2000-e-de-outros-ordinais/16428
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def to_ordinal(self, value):
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# Before changing this function remember this is used by pt-BR
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# so act accordingly
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self.verify_ordinal(value)
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result = []
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value = str(value)
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thousand_separator = ''
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for idx, char in enumerate(value[::-1]):
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if idx and idx % 3 == 0:
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thousand_separator = self.thousand_separators[idx]
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if char != '0' and thousand_separator:
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# avoiding "segundo milionésimo milésimo" for 6000000,
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# for instance
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result.append(thousand_separator)
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thousand_separator = ''
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result.append(self.ords[idx % 3][int(char)])
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result = ' '.join(result[::-1])
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result = result.strip()
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result = re.sub('\\s+', ' ', result)
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if result.startswith('primeiro') and value != '1':
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# avoiding "primeiro milésimo", "primeiro milionésimo" and so on
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result = result[9:]
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return result
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def to_ordinal_num(self, value):
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# Before changing this function remember this is used by pt-BR
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# so act accordingly
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self.verify_ordinal(value)
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return "%sº" % (value)
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def to_year(self, val, longval=True):
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# Before changing this function remember this is used by pt-BR
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# so act accordingly
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if val < 0:
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return self.to_cardinal(abs(val)) + ' antes de Cristo'
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return self.to_cardinal(val)
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def to_currency(self, val, currency='EUR', cents=True, seperator=' e',
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adjective=False):
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# change negword because base.to_currency() does not need space after
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backup_negword = self.negword
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self.negword = self.negword[:-1]
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result = super(Num2Word_PT, self).to_currency(
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val, currency=currency, cents=cents, seperator=seperator,
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adjective=adjective)
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# undo the change on negword
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self.negword = backup_negword
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# transforms "milhões euros" em "milhões de euros"
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try:
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cr1, _ = self.CURRENCY_FORMS[currency]
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except KeyError:
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raise NotImplementedError(
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'Currency code "%s" not implemented for "%s"' %
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(currency, self.__class__.__name__))
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for ext in (
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'milhão', 'milhões', 'bilião',
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'biliões', 'trilião', 'triliões'):
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if re.match('.*{} (?={})'.format(ext, cr1[1]), result):
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result = result.replace(
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'{}'.format(ext), '{} de'.format(ext), 1
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)
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# do not print "e zero cêntimos"
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result = result.replace(' e zero cêntimos', '')
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return result
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